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Ulysses 31

Do you know something from Greek mythology? Odysseus wandering through the Mediterranean on his return from the Trojan War until it can return to Ithaca with his wife Penelope and son Telemachus. The mighty Zeus on Mount Olympus, Polyphemus the Cyclops, and Hades, hell, the realm of the dead.

And do you remember this? I loved it.

feel I just wanted a little girl.

Stahni Zdarma Milena Velba

comes Christmas time peace, love and reconciliation. Open our hearts to the spirit of Bethlehem. May the example of the family of Nazareth comforting our homes and open a glimmer of hope.



A light coming from the east, opening the door to Christmas, time to be born of hope, solidarity and love.




May this Christmas I want to convert each flower, each pain star, every smile and every tear in a sweet heart abode for Jesus, our Savior.



is the desire of the management team and teachers of the School Fray Luis Beltrán

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Spanish and American Dates [The Problem of the Week] The age of the grandfather

several weeks ago proposed this little problem to the apprentices:

Mauritius, the grandfather of Joseph, is certainly not the centenary, but very old. We can say that last year, his age was a multiple of 8, and that next year is divisible by 7. How old is Mauritius?

The solution can be found under the interesting picture that we propose.

[Matenavegando mathematicians looking for long-lived, we have found the life of Leopold Vietoris an interesting article published Gaussianos.com . Vietoris was a mathematician Austrian born in 1891, which made important contributions in the field of topology. It is possible, according to this article, which is the mathematical Vietoris oldest known, for he died in 2002 at 110 years old. It is also the oldest Austrian, and her second marriage is the seventh longest marriage by adding the age of both spouses, as his second wife died in 101. The list is long-lived marriages in this wikipedia article.]

Solution:

The problem is to find a multiple of 8 and a multiple of 7 to differentiate by 2 units. Once found, the age of Mauritius will be the middle number.

multiples of 8 are 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120 ...

The multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105, 112, 119 ...

As Mauritius is not centenary, multiples greater than 100 we can rule out.

If you look carefully, there are two candidate pairs: 40 and 42 on one side, 96 and 98 on the other. But in the first case of Mauritius would be the age of 41 years, and this is no old age. The second case is more logical age Mauritius must be 97 years . Thus the previous year of age was 96 years (multiple of 8) and next year will be his age 98 years (multiple of 7).

Enlargement:

Such exercises can be solved by mathematical tools called congruences . In mathematical language, if we call x the age of Mauritius, then:

x ≡ 1 (mod 8)

x ≡ -1 (mod 7) ≡

The symbol is like sign of the same but with three horizontal lines instead of two, and in this context means is consistent with . For the properties of congruences, the second equation can be replaced by x ≡ 6 (mod 7)

As the greatest common divisor of 7 and 8 is equal to 1, the Chinese remainder theorem assures us that this system in congruences has a solution. To find the solution can be carried out as follows:

The two previous equations would be the same as saying:

x = 1 + 8k

x = 6 + 7j, where k and j represent any integer.

Multiplying the first equation by 7 and the second for 8 are:

7x = 7 + 56k

8x = 48 + 56j

Subtracting the second equation minus the first and we have:

x = 41 + 56 (j - k)

As k and j are arbitrary integers, the difference between them is also an arbitrary integer, then x is equal to 41 plus a multiple of 56 arbitrary:

x = 41 + 56mm, or what is the same:

x ≡ 41 (mod 56)

We have therefore to x can take the values \u200b\u200b41, 97, 153, 209, 265, ... And could even take negative values, such as -15, -71, -127, -183, -239, ...

Of all the possible solutions for x, we choose the most logical, 97, and therein lies our answer.

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STAGE ONE COMPLETED

Then came New Year ...



The tempera been completed, a few leaves have fallen, the crayons are cortitos ...
But how many things we have today in the courtroom the first day were not: your drawings in a corner, a broken toy (probably unintentionally), the folder that you've started Traveling with your family remember? Loupes with which investigated and the clothes they play ... the brush, the palette ...
Many memories will remain in our hearts ... certainly feel that it was a moment in our lives but we were special to share and give us as we are.
made us feel we chose the best profession in the world.


THANKS!
☼ Red Room
Board ☼
Celeste ☼ Yellow Room
☼ Blue Room

Love is playing paths toward us, and give thanks to life for having traveled.

Today I can only tell you that it will be hard to say goodbye and that this bit of your childhood, for always going to unite. ADRIANA
WITHIN WITHIN
SILVANA
WITHIN WITHIN
IVANA MARIA DE LOS ANGELES

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seemingly meaningless letters


1. Voted, and I was like I was.

2. I read a book that is not bad at all (see right).

3. Prepare a trip to not know what day.

4. I make clean, I have read, do I write, I make study, I have like, do I sleep.

5. I make alive.

6. I wish more closely.

7. Toco heat. Heat the cold.

8. Food. Quenched.

9. Dream.

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RECEIVE AWARD ...

Teacher: Mariela Salinas

Grade 6 Fray Luis Beltrán

Esc

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Contest "researchers with science"

We told them that this work students in Grade 6 "A" won, a "National Level", one of the positions of the contest and to receive the award went to the province of Mendoza. Students prepared for the campaign "researchers with science" developed the following guide work based on material provided by the makers of the competition (student booklet, film and CD):

Science: Investigate Science Competition
Introduction:
1) Read the contest rules and complete.

Theme:
Participants:
Labour participation
Date:
2) Assemble working groups.
3) Browse to find the booklet "researchers with science student."
4) Read the answer 6
a) What is carbon monoxide?
b) What are the characteristics?
c) Who is produced?
d) What time we can carbon monoxide poisoning?
e) Why should the majority of poisoning?
5) Read the theme "Natural Gas and secure energy" and write down what your parents tell you or someone older.
6) Read the page. 7, summarize the production issue and make a concept map.
7) Draw a section of the subsoil and indicate the places where it is most likely to find natural gas and how to extract it.
8) Make the experience of the page. 8 and complete the activities.
9) Observe the graphs on page 9 to complete the scheme.
10) Remember the experience we made with balloons and answer questions page. 10
11) Watching the film, read page 11 and explain the safe travel of the gas.
12) Search and paste images from devices that use natural gas.
13) the experiment on page 12. Then write a conclusion that includes all properties natural gas.
14) A map of Argentina noted the pipeline of our country and after completing the activities on page 13.
15) Make the experiences of the page. 14 and 15 and then write your conclusions.
16) Browse in the computer room's CD "researchers with science" and respond
a) What is the first action of ECOGAS? Why is it done?
b) Where do you come home networks?
c) What is the service area of \u200b\u200bECOGAS?
17) Complete the diagram.

18) Complete the table on page 21 with the help of someone older.

19) Carry out the activity page. 22.
20) Summarize the information on pages 17, 18, 19 and 20 to perform the closing activity will allow us to participate in the contest. I followed the tips that appear there and good luck.


Remember: At the end of the campaign must make a poster for the prevention of accidents by carbon monoxide poisoning using your favorite technique: collage, painting with watercolors, photographs, etc.


Development
After the campaign was planned, organized thinking; public they would be addressed, how to reach the largest audience, with media that were available and chose the following media to disseminate advice to avoid Carbon monoxide poisoning:
 Brochures.  Give
messages in the hours on duty at the school.  Post
councils in the school blog (esc-fray-luis-beltran.blogspot.com).  Post
advice online at the "facebook" BN BD Program (Good Night Good Morning) that transmitted by Channel 5 in San Juan every night at 24h and repeated the 7hs.  addition
prepared at the time of publication Power Point computer with the same intention.


Finally we made posters for the group in which were set out and drew the tips to prevent carbon monoxide poisoning.
The experience was very constructive, it could detect, investigate, apply and integrate knowledge from several areas of the curriculum and above all provide a service to the community by the students of 6 th "A" school Fray Luis Beltrán multipliers.
The winning team was composed of Shaira July, Dayana Rul, Maria Jose Resa, and Maximiliano Barboza.

School: Fray Luis Beltrán
County: San Juan
Teacher: Mario Salinas - 6 A
Cycle school: 2010

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Blog temporarily closed

Those readers who wish to leave your comments, however, do so.

reply comments will be necessary, as usual.

Thank you, and to meet again, perhaps.

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Pilcher Gaucho ... BY NOVEMBER 10! Argentine customs

'''''' ARGENTINA'''Canta SOLEDAD "Gaucho "''''' Pilchas - The best video clips right here

Are

Woke Up Vomiting And Diarhhea

I have no

Religion. Or penis.

Yesterday I went to the concentration in defense of the secular state. There were many placards, some with better taste than others. The best, in my opinion, that as I can transcribe here:

"Religion is like a penis.'s Good to have one and be proud. But it is wrong to want to stick it to others by force." There

stated.

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[The Problem of the Week] Long sequence of addition and subtraction to solve Kakuro Tutorial

A new problem, quite simple if we approach it properly.

In a book has appeared rather long operation:

999 to 998 + 997-996 + 995-994 + ... + 5 to 4 + 3 - 2 + 1

words, this is going adding and subtracting numbers in decreasing sequence, from the 999 to 1, the odd numbers are added, the pairs are subtracted. Can you calculate this operation?

The solution, as always, below, so do not expect to see our deductions.

[This illustration matenavegábamos found while looking for images of sums, has been extracted from this page . As you can see, there is a table that presents all sums of two squares less than or equal to 100. What's so funny? Fermat realized that these sums could give composite numbers and prime numbers, but the premiums collected were those of the form 4n +1, that is, that, when divided by 4 gives the remainder 1 (with the exception of 2, that is prime, is the sum of two squares and does not give remainder 1 when divided by 4). In the table are appearing all the cousins \u200b\u200band none of 4n +1 primes 4n +3. This led to enunciate the so-called Fermat Theorem Christmas, a name sometimes given because it is in a letter to Marin Mersenne dated December 25, 1640]

Solution:

may seem silly, we will add to the sum the term zero, which does not alter the result, and wrote:

999 to 998 + 997-996 + 995-994 + ... + 5 - 4 + 3 - 2 + 1 - 0

This way we can match the numbers:

(999-998) + (997-996) + (995-994) + ... + (5 - 4) + (3 - 2) + (1 - 0)

Each pair gives the same result, 1, then we have a large sum of ones. How many around there? Given that the numbers ranging from 999 to 0, there are exactly 1000 numbers, and therefore there are 500 pairs. (The zero we have added to match pairs and counting easier). There are 500 pairs, each one gives 1, then the sum is 500 :

1 + 1 + 1 + ... [500 times] ... + 1 + 1 + 1 = 500.

Note: this problem, slightly modified, has been taken from the textbook 4 º ESO publisher Anaya.

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If you call at two in the morning, after an hour and a half trying to sleep, and when it seems you're in that limbo that is neither this world nor the dreams, to kill a spider, what are you doing? I got up and killed her.

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present this tutorial, which is a English translation of that comes as a flash animation page of the Japanese magazine Nikoli .
The numeric Kakuro is a hobby, family, sudoku. Kakuro

The numbers must be partitioned into sums of smaller numbers to be placed in the appropriate cells.

white cells must be filled with numbers from 1 to 9. For example, in the cells listed below, the numbers must add up to 5, and in principle can come in any order (could be, for example, 1, 4, 4 and 1, 2 and 3, 3 and 2).

listed below in the cells, the numbers must add up to 14.

numbers can not be repeated in consecutive cells. The following example may be correct:

But the following example it is not, it should not repeat numbers in the sum:

The following figure There are two numbers 1, but it is correct, because they are not in consecutive cells and not in the same amount:

Let's start solving the kakuro. Look at the sum 4 below on the right. To get 4 can only be done by adding 1 and 3, but do not know in what order:

But if you look at the 3 which is on the right, only can be obtained by adding 1 and 2, and numbers can be placed in two possible orders:

The common number is the sum of 4 and of 3 is 1, then 1 in the cell must be common to both:

Placing on 1 then you can fill cells missing:

continue with the further sum of 3 that is in the center. There are two possibilities:

But the two possibilities represented, is valid only on the left, because the right of the 2 would be repeated in the same row.

We can complete the sum 10. Just keep in mind that four boxes totaling 10 only allowed the numbers 1, 2, 3 and 4. As already in place on 1 and 2, just fill with 3 and 4 properly so there is no repetition in the columns.

Now let's look at another type of reasoning. 6 Look at the sum of two squares, center left, and the sum 14 in column to the left. Both sums have a common box.

6 The sum of two squares can be expressed in several ways: 1 and 5, 2 and 4. The same goes with 14, which can be broken down into 5 and 9, or at 6 and 8. But if the marked box is a number equal to or greater than 6, it would not be compatible with the sum 6, and if the box indicated the number was equal to or less than 4, then to complete the $ 14 would be 10 or older. Then the following two options are wrong:

The number of box must be marked, therefore, a 5, so that is compatible with the two sums.

Following this type of logical reasoning, you can complete the kakuro in the only way possible.

To solve the Kakuro is very useful to know the list of unique sums . For example, two cells or boxes, 3 can only be obtained with 1 and 2, and 4 with 1 and 3, in addition to 17 can only be obtained with 8 and 9, and 16 with 7 and 9. With three cells, 6 can only be obtained with 1, 2 and 3, 7 to 1, 2 and 4, in addition to 24 can only be obtained with 7, 8 and 9, and 23 with 6, 8 and 9. A complete list of all amounts only by the number of boxes is, for example in this direction .

This tutorial can be expanded more, but each person, with practice and developing their own logic resources to be able to go face Kakuro increasingly advanced level. One page recommended to play online kakuro is www.kakuro.com .

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[The Problem of the Week ] Counting decimal

The new boat tour of our school, the first issue of the week is as follows:

Some numbers may have many decimal places, even infinite. Consider the decimal number

0'012345670123456701234567 ...

If you look you will see that decimals are repeated in a succession very easy. Note that the first decimal place is 0, the second a 1, the third a 2, etc., And if you keep counting, the figure is, for example, in tenth place is a 1, and the figure is twentieth place is a 3.

Would you know how to tell which decimal is in the thousandths place?

We put the image shown below, and then put the solution.

[In the picture we see the Eye of Horus, divided into parts, each corresponding to a fraction. The Egyptians did not use our Hindu-Arabic positional system, and smaller amounts represent the unit used unit fractions, ie with a numerator equal to one. They were able to express any fractional amount adding unit fractions. The image and more information on Egyptian fractions, can be found on page corresponding wikipedia]

Solution:

It is clear that the recurring decimal eight eight, and also that the 7 is in all positions multiples of eight: the eighth decimal place is 7, the sixteenth decimal is 7, the twenty-fourth again becomes 7, etc..

Coincidentally, a thousand is a multiple of eight, then the decimal is in the thousandths place is 7 .

Note: the number of which is our problem is a pure periodic infinite decimal. Matenavegante as any apprentice should know, this number is an expression as a fraction. In this case the fraction is

This fraction is irreducible, because numerator and denominator have no common prime factors. Specifically, 1234567 = 127 ° 9721, and 99,999,999 = 3 • 3 • 11 · 73 ° 101 ° 137. Factorizations we have done with this calculator page. However, on that same page is another calculator passing periodic infinite decimal fraction , but Wrong.